Initializing help system before first use

Find largest-area inscribed polygon


Type: Programming
Rating: 2 (easy-medium)
Description: Given n, find the n-sided polygon of largest area inscribed in the unit circle.
File(s): polygon.py


polygon.py
import xpress as xp
import math
import matplotlib.pyplot as plt
from matplotlib.path import Path
import matplotlib.patches as patches

# Problem: given n, find the n-sided polygon of largest area inscribed
# in the unit circle.
#
# While it is natural to prove that all vertices of a global optimum
# reside on the unit circle, here we formulate the problem so that
# every vertex i is at distance rho[i] from the center and at angle
# theta[i]. We would certainly expect that the local optimum found has
# all rho's are equal to 1.

N = 9

Vertices = range(N)

# Declare variables
rho = [xp.var(name='rho_{}'.format(i), lb=1e-5, ub=1.0) for i in Vertices]
theta = [xp.var(name='theta_{}'.format(i), lb=-math.pi, ub=math.pi)
         for i in Vertices]

p = xp.problem()

p.addVariable(rho, theta)

# The objective function is the total area of the polygon. Considering
# the segment S[i] joining the center to the i-th vertex and A(i,j)
# the area of the triangle defined by the two segments S[i] and S[j],
# the objective function is
#
# A[0,1] + A[1,2] + ... + A[N-1,0]
#
# Where A[i,i+1] is given by
#
# 1/2 * rho[i] * rho[i+1] * sin (theta[i+1] - theta[i])

p.setObjective(0.5 * (xp.Sum(rho[i] * rho[i-1] * xp.sin(theta[i] - theta[i-1])
                             for i in Vertices if i != 0)
                      # sum of the first N-1 triangle areas
                      + rho[0] * rho[N-1] * xp.sin(theta[0] - theta[N-1])),
               sense=xp.maximize)  # plus area between segments N and 1

# Angles are in increasing order, and should be different (the solver
# finds a bad local optimum otherwise

p.addConstraint(theta[i] >= theta[i-1] + 1e-4 for i in Vertices if i != 0)

# solve the problem

p.solve()

# The following command saves the final problem onto a file
#
# p.write('polygon{}'.format(N), 'lp')

rho_sol = p.getSolution(rho)
theta_sol = p.getSolution(theta)

x_coord = [rho_sol[i] * math.cos(theta_sol[i]) for i in Vertices]
y_coord = [rho_sol[i] * math.sin(theta_sol[i]) for i in Vertices]

vertices = [(x_coord[i], y_coord[i]) for i in Vertices] + \
           [(x_coord[0], y_coord[0])]

moves = [Path.MOVETO] + [Path.LINETO] * (N-1) + [Path.CLOSEPOLY]

path = Path(vertices, moves)

fig = plt.figure()
sp = fig.add_subplot(111)

patch = patches.PathPatch(path, lw=1)

sp.add_patch(patch)

# Define bounds of picture, as it would be [0,1]^2 otherwise
sp.set_xlim(-1.1, 1.1)
sp.set_ylim(-1.1, 1.1)

plt.show()

© 2001-2019 Fair Isaac Corporation. All rights reserved. This documentation is the property of Fair Isaac Corporation (“FICO”). Receipt or possession of this documentation does not convey rights to disclose, reproduce, make derivative works, use, or allow others to use it except solely for internal evaluation purposes to determine whether to purchase a license to the software described in this documentation, or as otherwise set forth in a written software license agreement between you and FICO (or a FICO affiliate). Use of this documentation and the software described in it must conform strictly to the foregoing permitted uses, and no other use is permitted.