#!/bin/env python
#
# This example shows how to visualize the BB tree of a problem after
# (partially) solving it.
#
# Note: assumes all branches are binary
import networkx as nx
import xpress as xp
from matplotlib import pyplot as plt
def postorder_count(node):
"""Recursively count nodes to compute the cardinality of a subtree for
each node"""
card = 0
if node in left.keys(): # see if node has a left key
postorder_count(left[node])
card += card_subtree[left[node]]
if node in right.keys():
postorder_count(right[node])
card += card_subtree[right[node]]
card_subtree[node] = 1 + card
def setpos(T, node, curpos, st_width, depth):
"""
Set position depending on cardinality of each subtree
"""
# Special condition: we are at the root
if node == 1:
T.add_node(node, pos=(0.5, 1))
# Use a convex combination of subtree comparison and
# depth to assign a width to each subtree
alpha = .1
if node in left.keys():
# X position in the graph should not just depend on depth,
# otherwise we'd see a long and thin subtree and it would just
# look like a path
leftwidth = st_width * (alpha * .5 + (1 - alpha) *
card_subtree[left[node]] /
card_subtree[node])
leftpos = curpos - (st_width - leftwidth) / 2
T.add_node(left[node], pos=(leftpos, - depth))
T.add_edge(node, left[node])
setpos(T, left[node], leftpos, leftwidth, depth + 1)
if node in right.keys():
rightwidth = st_width * (alpha * .5 + (1 - alpha) *
card_subtree[right[node]] /
card_subtree[node])
rightpos = curpos + (st_width - rightwidth) / 2
T.add_node(right[node], pos=(rightpos, - depth))
T.add_edge(node, right[node])
setpos(T, right[node], rightpos, rightwidth, depth + 1)
def storeBBnode(prob, Tree, parent, newnode, branch):
# Tree is the callback data, and it's equal to T
if branch == 0:
left[parent] = newnode
else:
right[parent] = newnode
T = nx.Graph()
left = {}
right = {}
card_subtree = {}
pos = {}
p = xp.problem()
p.read('sampleprob.mps.gz')
p.addcbnewnode(storeBBnode, T, 100)
p.controls.maxnode = 40000 # Limit the number of nodes inserted in the graph
p.solve()
postorder_count(1) # assign card_subtree to each node
# determine the position of each node
# depending on subtree cardinalities
setpos(T, 1, 0.5, 1, 0)
pos = nx.get_node_attributes(T, 'pos')
nx.draw(T, pos) # create BB tree representation
plt.show() # display it; you can zoom indefinitely and see all subtrees
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