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Chgprobs - Working with multiple problems


Type: Programming
Rating: 2 (easy-medium)
Description: This example defines 3 very small problems, making changes to the problem definition after matrix generation and retrieving solution information. It also shows BCL warnings.
File(s): xbexpl.c


xbexpl.c
/********************************************************
  BCL Example Problems
  ====================

  file xbexpl.c
  `````````````
  Working with multiple problems.

  (c) 2008 Fair Isaac Corporation
      author: S.Heipcke, Jan. 2000, rev. Mar. 2011
********************************************************/

#include <stdio.h>
#include "xprb.h"

/********************************************************/
/* This file illustrates how to                         */
/* - do changes to the problem definition               */
/* - retrieve solution information                      */
/* - define and work with several problems              */
/*                                                      */
/* Define at least one of the following options. It is  */
/* possible to define all together. In this case the    */
/* last function (expl5) that shows how to switch       */
/* between problems is activated too.                   */
/********************************************************/
#define CHGCTR                 /* Accessing and modifying constraints */
#define CHGVAR                 /* Accessing and modifying variables   */
#define UNBOUNDED              /* Solve a small unbounded problem     */

void expl2(void);
void expl3(void);
void expl4(void);
void expl5(void);

XPRBprob prob2, prob3, prob4;  /* Problem definitions */

/***********************************************************************/
int main(int argc, char **argv)
{
#ifdef CHGCTR
 expl2();
#endif
#ifdef CHGVAR
 expl3();
#endif
#ifdef UNBOUNDED
 expl4();
#ifdef CHGCTR
#ifdef CHGVAR
 expl5();
#endif
#endif
#endif

 return 0;
}
/***********************************************************************/

    /**** Expl 2: changing bounds and operations on constraints ****/
void expl2(void)
{
 XPRBvar x[5];
 XPRBctr ctr[4], cobj;
 double objcof[]={2.0,1.0,1.0,1.0,0};
 int i;

 prob2=XPRBnewprob("expl2");       /* Create a new problem */

                /* Define 5 integer variables in 0,...,100 */
 for(i=0;i<5;i++) x[i]=XPRBnewvar(prob2,XPRB_UI,XPRBnewname("x_%d",i),0,100);

                /* Create the constraints:
                   ctr0: x0 +10 <= x1
                   ctr1: x1     <= x3
                   ctr2: x1 + 8 <= x2 */
 ctr[0]=XPRBnewprec(prob2,"ctr0",x[0],10,x[1]);
 ctr[1]=XPRBnewprec(prob2,"ctr1",x[1],0,x[3]);
 ctr[2]=XPRBnewprec(prob2,"ctr2",x[1],8,x[2]);

 cobj = XPRBnewctr(prob2,"OBJ",XPRB_N);
 for(i=0;i<5;i++) XPRBaddterm(cobj,x[i],objcof[i]);
 XPRBsetobj(prob2,cobj);            /* Select objective function */
 XPRBsetsense(prob2,XPRB_MINIM);    /* Set objective sense to minimization */

 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
 XPRBexportprob(prob2,XPRB_LP,"expl2");  /* Matrix generation and output */
 XPRBprintprob(prob2);              /* Print current problem definition */

 XPRBlpoptimize(prob2,"");          /* Solve the LP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
 printf("Objective: %g\n",XPRBgetobjval(prob2));
 for(i=0;i<4;i++)                   /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));
 printf("\n");

 XPRBsetrange(ctr[0],-15,-5);       /* Transform ctr[0] into range constraint */
 printf("\n<<<<<<<<Constraint transformed into range:>>>>>>>>\n");
 XPRBprintprob(prob2);              /* Print current problem definition */
 for(i=0;i<4;i++)
 { XPRBprintvar(x[i]); printf(" "); }  /* Print new variable bounds */
 printf("\n");
 XPRBmipoptimize(prob2,"");         /* Solve MIP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
 printf("Objective: %g\n",XPRBgetobjval(prob2));
 for(i=0;i<4;i++)                   /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));
 printf("\n");

 XPRBsetctrtype(ctr[0],XPRB_L);     /* Change ctr[0] back to constraint */
 printf("\n<<<<<<<<Constraint restored to inequality:>>>>>>>>\n");
 XPRBprintprob(prob2);              /* Print current problem definition */
 XPRBsetterm(ctr[0],NULL,-10);      /* Set new RHS value */
 printf("<<<<<<<<Restore original RHS value:>>>>>>>>\n");
 XPRBprintprob(prob2);              /* Print current problem definition */

 XPRBsetlb(x[1],15);                /* Change the bound on a variable */
 printf("<<<<<<<<Variable bound changed:>>>>>>>>\n");
 for(i=0;i<4;i++)
 { XPRBprintvar(x[i]); printf(" "); }  /* Print new variable bounds */
 printf("\n");
 XPRBmipoptimize(prob2,"");         /* Solve MIP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
 printf("Objective: %g\n",XPRBgetobjval(prob2));
 for(i=0;i<4;i++)                   /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));
 printf("\n");

    /**** Change constraint coefficient and RHS ****/
 XPRBsetterm(ctr[1],x[1],-3);       /* ctr1: x1 <= 3*x3 */
 XPRBaddterm(ctr[0],NULL,-10);      /* ctr0: x0 + 20 <= x1 */
 printf("\n<<<<<<<<Constraint coefficient and RHS changed:>>>>>>>>\n");
 for(i=0;i<3;i++) XPRBprintctr(ctr[i]);
 for(i=0;i<4;i++)
 { XPRBprintvar(x[i]); printf(" "); }  /* Print new variable bounds */
 printf("\n");
 XPRBmipoptimize(prob2,"");         /* Re-generate the matrix and solve MIP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
 printf("Objective: %g\n",XPRBgetobjval(prob2));
 for(i=0;i<4;i++)                   /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));
 printf("\n");

    /**** Change constraint type ****/
 XPRBsetctrtype(ctr[2],XPRB_G);     /* ctr2: x1 + 8 >= x2 */
 printf("\n<<<<<<<<Constraint type changed:>>>>>>>>\n");
 for(i=0;i<3;i++) XPRBprintctr(ctr[i]);
 for(i=0;i<4;i++)
 { XPRBprintvar(x[i]); printf(" "); }  /* Print variable bounds */
 printf("\n");
 XPRBmipoptimize(prob2,"");         /* Re-generate the matrix and solve MIP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
 printf("Objective: %g\n",XPRBgetobjval(prob2));
 for(i=0;i<4;i++)                   /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));
 printf("\n");

    /**** Add another constraint ****/
 ctr[3]=XPRBnewprec(prob2,"ctr3",x[0],37,x[2]);  /* ctr4: x0 +37<= x2 */
 printf("\n<<<<<<<<Constraint added:>>>>>>>>\n");
 XPRBprintprob(prob2);
 for(i=0;i<4;i++)
 { XPRBprintvar(x[i]); printf(" "); }  /* Print variable bounds */
 printf("\n");
 XPRBmipoptimize(prob2,"");         /* Re-generate the matrix and solve MIP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
 printf("Objective: %g\n",XPRBgetobjval(prob2));
 for(i=0;i<4;i++)                   /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));
 printf("\n");

    /**** Delete a constraint ****/
 XPRBdelctr(ctr[2]);
 printf("\n<<<<<<<<Constraint deleted:>>>>>>>>\n");
 XPRBprintprob(prob2);
 for(i=0;i<4;i++)
 { XPRBprintvar(x[i]); printf(" "); }  /* Print variable bounds */
 printf("\n");
 XPRBmipoptimize(prob2,"");         /* Re-generate the matrix and solve MIP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
 printf("Objective: %g\n",XPRBgetobjval(prob2));
 for(i=0;i<4;i++)                   /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));
 printf("\n");
}

    /**** Expl 3: Knapsack problem: accessing variables ****/
void expl3(void)
{
 XPRBvar x[4];
 XPRBctr ctr, cobj;
 double coeff[]={30.0,32.0,27.0,11.0};
 double objcof[]={9.0,15.0,8.0,3.0}, lbd, ubd;
 int i;

 prob3=XPRBnewprob("expl3");        /* Create a new problem */

 for(i=0;i<4;i++)                   /* Define 4 binary variables */
  x[i]=XPRBnewvar(prob3,XPRB_BV,XPRBnewname("x_%d",i),0,1);

                        /* Create the knapsack constraint:
                           sum_i coeff[i]*x[i] <= 70  */
 ctr = XPRBnewctr(prob3,"sumkn",XPRB_L);
 for(i=0;i<4;i++) XPRBaddterm(ctr,x[i],coeff[i]);
 XPRBaddterm(ctr,NULL,70);

 cobj = XPRBnewctr(prob3,"OBJ",XPRB_N);
 for(i=0;i<4;i++) XPRBaddterm(cobj,x[i],objcof[i]);
 XPRBsetobj(prob3,cobj);            /* Select objective function */

/* XPRBprintprob(prob3); */              /* Uncomment to print the problem */
 XPRBexportprob(prob3,XPRB_MPS,"expl3"); /* Matrix output in MPS format */
 XPRBsetsense(prob3,XPRB_MAXIM);         /* Change to maximization */
 XPRBmipoptimize(prob3,"");         /* Solve MIP */
 printf("Objective: %g\n",XPRBgetobjval(prob3));   /* Get objective value */
 for(i=0;i<4;i++)                   /* Print the solution */
  printf("%s: %g (rc:%g),\n",XPRBgetvarname(x[i]),XPRBgetsol(x[i]),
    XPRBgetrcost(x[i]));
 printf("Dual: %g, slack: %g\n",XPRBgetdual(ctr),XPRBgetslack(ctr));
                                    /* Print dual & slack values */

 printf("\n<<<<<<<<Variable type changed from BV to UI>>>>>>>>\n");
 XPRBsetvartype(x[1],XPRB_UI);      /* Change variable type */
 XPRBgetbounds(x[1], &lbd, &ubd);   /* Get variable bounds */
 printf("%s: bounds: %g %g, type: %d, index: %d\n",
    XPRBgetvarname(x[1]),lbd, ubd, XPRBgetvartype(x[1]),XPRBgetcolnum(x[1]));
 XPRBmipoptimize(prob3,"");         /* Re-solve MIP */
 printf("Objective: %g\n",XPRBgetobjval(prob3));   /* Get objective value */


 printf("\n<<<<<<<<Variable bound changed: no matrix regeneration>>>>>>>>\n");
 XPRBsetub(x[1],3);                 /* Change variable bound */
 XPRBgetbounds(x[1], &lbd, &ubd);   /* Get variable bounds */
 printf("%s: bounds: %g %g, type: %d, index: %d\n",
    XPRBgetvarname(x[1]),lbd, ubd, XPRBgetvartype(x[1]),XPRBgetcolnum(x[1]));
 XPRBmipoptimize(prob3,"");         /* Re-solve MIP */
printf("Objective: %g\n",XPRBgetobjval(prob3));   /* Get objective value */
 for(i=0;i<4;i++)                   /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));

 printf("\n\n<<<<<<<<Variable type changed from UI to PI>>>>>>>>\n");
 XPRBsetvartype(x[1],XPRB_PI);      /* Change variable type */
 XPRBsetlim(x[1],2);                /* set the integer limit for
                                       the partial integer variable */
 XPRBprintvar(x[1]); printf("\n");  /* Print current variable definition */
 XPRBmipoptimize(prob3,"");         /* Re-solve MIP */
 printf("Objective: %g\n",XPRBgetobjval(prob3));   /* Get objective value */
 for(i=0;i<4;i++)                   /* Print the solution */
  printf("%s: %g (rc:%g),\n",XPRBgetvarname(x[i]),XPRBgetsol(x[i]),
    XPRBgetrcost(x[i]));
 printf("Dual: %g, slack: %g\n",XPRBgetdual(ctr),XPRBgetslack(ctr));
                                    /* Print dual & slack values */
}

    /****Expl 4: a small unbounded problem ****/
void expl4(void)
{
 XPRBvar x[2];
 XPRBctr ctr;
 double objcof[]={1.0,1.0};
 int i;

 prob4=XPRBnewprob("expl4");         /* Create a new problem */

                /* Define 2 variables in [0,PLUSINFINITY] */
 for(i=0;i<2;i++) x[i]=XPRBnewvar(prob4,XPRB_PL,XPRBnewname("x_%d",i),0,XPRB_INFINITY);

                /* Create the constraints:
                   ctr0: 4*x0 + x1 >= 4
                   ctr1: x0 + x1   >= 3
                   ctr2: x0 + 2*x1 >= 4 */
 ctr=XPRBnewctr(prob4,"c1",XPRB_G);
 XPRBaddterm(ctr,x[0],4);
 XPRBaddterm(ctr,x[1],1);
 XPRBaddterm(ctr,NULL,4);

 ctr=XPRBnewctr(prob4,"c2",XPRB_G);
 XPRBaddterm(ctr,x[0],1);
 XPRBaddterm(ctr,x[1],1);
 XPRBaddterm(ctr,NULL,3);

 ctr=XPRBnewctr(prob4,"c3",XPRB_G);
 XPRBaddterm(ctr,x[0],1);
 XPRBaddterm(ctr,x[1],2);
 XPRBaddterm(ctr,NULL,4);

 ctr = XPRBnewctr(prob4,"OBJ",XPRB_N);
 for(i=0;i<2;i++) XPRBaddterm(ctr,x[i],objcof[i]);
 XPRBsetobj(prob4,ctr);                     /* Select objective function */

/* Try out the effect of solving without presolve:
 XPRSsetintcontrol(XPRBgetXPRSprob(prob4), XPRS_PRESOLVE, 0);
 XPRSsetintcontrol(XPRBgetXPRSprob(prob4), XPRS_MIPPRESOLVE, 0);
*/
 XPRBsetsense(prob4,XPRB_MAXIM);      /* Change to maximization */
 XPRBlpoptimize(prob4,"");            /* Solve the LP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob4),XPRBgetlpstat(prob4),XPRBgetmipstat(prob4));
 printf("Objective: %g\n",XPRBgetobjval(prob4));   /* Get objective value */
 for(i=0;i<2;i++)                     /* Print solution values */
  printf("%s:%g ", XPRBgetvarname(x[i]), XPRBgetsol(x[i]));
 printf("\n");
}

    /***Expl5: Working with different problems****/
void expl5(void)
{
 int i;
    /**** Re-solve problem 2 ****/
 printf("\n<<<<<<<<Re-solve prob2>>>>>>>>\n");
 XPRBsetsense(prob2,XPRB_MINIM);      /* Change to minimization */
 XPRBmipoptimize(prob2,"");           /* Solve global */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob2),XPRBgetlpstat(prob2),XPRBgetmipstat(prob2));
  printf("Objective: %g\n",XPRBgetobjval(prob2));   /* Get objective value */
 for(i=0;i<4;i++)                     /* Print solution values */
  printf("x_%d:%g ", i,
   XPRBgetsol(XPRBgetbyname(prob2,XPRBnewname("x_%d",i),XPRB_VAR)));

    /**** Delete problem 4 ****/
 printf("\n\n<<<<<<<<Delete prob4>>>>>>>>\n");
 XPRBprintprob(prob4);                /* Print the problem def. */
 XPRBdelprob(prob4);                  /* Delete the problem */

    /**** Re-solve problem 3 ****/
 printf("<<<<<<<<Re-solve prob3 and print it>>>>>>>>\n");
 XPRBprintprob(prob3);                /* Print the problem def. */
 XPRBsetsense(prob3,XPRB_MAXIM);      /* Change to maximization */
 XPRBmipoptimize(prob3,"");           /* Solve MIP */
 printf("Problem status: %d  LP status: %d  MIP status: %d\n",
    XPRBgetprobstat(prob3),XPRBgetlpstat(prob3),XPRBgetmipstat(prob3));
  printf("Objective: %g\n",XPRBgetobjval(prob3));   /* Get objective value */
 for(i=0;i<4;i++)                     /* Print solution values */
  printf("x_%d:%g ", i,
   XPRBgetsol(XPRBgetbyname(prob3,XPRBnewname("x_%d",i),XPRB_VAR)));
 printf("\n");
}

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