import xpress as xp

x = xp.var()
y = xp.var(name='myvar')

a = x + 2*y
b = 3*x
c = y**2 + x**2 - 6*x
d = x**5 - 7*x  # nonlinear expression

print (a.extractLinear())  # will print "([C1, myvar], [1, 2])"
assert (a.extractLinear() == ([x, y], [1, 2]))

print (b.extractLinear())  # will print "([C1], [3])"
print (c.extractLinear())  # will print "([C1], [-6])"
print (d.extractLinear())  # will print "([C1], [-7])"

1. Note that this operator returns variable objects, not indices, in the vars portion of the output tuple. To obtain indices, use the problem.getIndex function. Printing these lists will show the name of the associated variables, as determined by the user when creating the variable with the name argument or, if name was not provided, it will show the name as determined by the Optimizer's library (default variable names are "C"+index). See also the Modelling chapter.

2. This operator is most useful only for linear expressions with more than one element. For nonlinear expressions, the function attempts to extract as much linear information it can, but will not be able to infer linearity apart from the most obvious cases. For example, for the expression x**4 + xp.log(xp.exp(y)), which contains the linear term y, the function will return ([],[]).