Initializing help system before first use

xpress.And

Purpose

Returns a logical AND of two or more binary variables or expressions.


Synopsis
xpress.And(variables)
Argument
variables 
A list/array of binary variables or binary expressions
Example
The following example shows how to use and to model various logical constraints: 
N = 10

p = xp.problem()  # Creates a problem

x = p.addVariables(N, vartype=xp.binary)  # Creates N binary variables

c = [1, 4, 7, 3, 5, 7, 8, 4, 4, 9]

# Sets a linear objective
p.setObjective (xp.Sum(c[i] * x[i] for i in range(N)))

# Linear constraint
p.addConstraint (xp.Sum(x) <= 6)

# Constrains the first x variable to be the conjunction of all other x's
p.addConstraint (x[0] == xp.And(x[1:]))

# Forces the logical AND between some logical expressions to
# be zero, i.e., at least one of them must be zero

p.addConstraint (xp.And([x[1] | x[4], x[2] | x[1], x[3] | x[6]]) == 0)
Further information
1. For AND functions, all variables and expressions must be binary; an error will be generated otherwise.
2. A function call xpress.And(x1,x2,...,xk) is equivalent to x1 and (x2 and (x3 and ... xk))...).
3. Note that since x1, x2, ..., xk, are binary variables, xpress.And(x1,x2,...,xk) is equivalent to xpress.min(x1,x2,...,xk).
Related topics
problem.addgencons, problem.delgencons, problem.getgencons, xpress.Or.

Parent Topic Xpress operators

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